Question

Prove that \[\begin{equation*} \frac{d}{dx} (3 \cos x - \cos 3x)= 6 \sin x \cos 2x. \end{equation*}\] For what two ranges of values of \(x\) between \(0\) and \(\pi\) is \[\begin{equation*} 3 \cos x - \cos 3x \end{equation*}\]

an increasing function of \(x\)?

Draw a rough sketch-graph of \(y = 3 \cos x - \cos 3x\) for values of \(x\) from \(0\) to \(\pi\), indicating clearly any maximum or minimum points.