A body moves in a straight line so that at time \(\quantity{t}{sec.}\) its velocity \(\quantity{v}{ft./sec.}\) is given by the formula\[ v= \frac{2t-1}{4(2t+1)}. \]

Find:

- the displacement of the body, measured from its position when \(t=0\), at the instant when its velocity is zero;
- the acceleration of the body at this instant.

[The numerical answer to (i) is required correct to two significant figures.]