By bracketing the terms in pairs, or otherwise, find the sum of \(2n\) terms of the series \[1^2-3^2+5^2-7^2+\cdots.\]
Hence show that the sum of \(2n+1\) terms is \(8n^2+8n+1\).
By bracketing the terms in pairs, or otherwise, find the sum of \(2n\) terms of the series \[1^2-3^2+5^2-7^2+\cdots.\]
Hence show that the sum of \(2n+1\) terms is \(8n^2+8n+1\).