The sum of the first \(2n\) terms of \[1,1,2,\frac{1}{2},4,\frac{1}{4},8,\frac{1}{8},16,\frac{1}{16},..\] is
\(2^n+1-2^{1-n}\),
\(2^n+2^{-n}\),
\(2^{2n}-2^{3-2n}\),
\(\frac{2^n-2^{-n}}{3}\).
The sum of the first \(2n\) terms of \[1,1,2,\frac{1}{2},4,\frac{1}{4},8,\frac{1}{8},16,\frac{1}{16},..\] is
\(2^n+1-2^{1-n}\),
\(2^n+2^{-n}\),
\(2^{2n}-2^{3-2n}\),
\(\frac{2^n-2^{-n}}{3}\).