Question

Solve for \(x\), \(y\) and \(z\) the equations: \[\begin{align*} 2x-y+z&{}=0,\\ 3y+z&{}=0,\\ x+y+az&{}=b, \end{align*}\]

where \(a\) and \(b\) are constants and \(a \neq 1\).

What happens if \(a=1\)?