\(3\cos \theta + 4\sin \theta\) may be written in the form \(r\cos(\theta - \alpha)\), where \(r > 0\).
Calculate the value of \(r\), and show that one value of \(\alpha\) is approximately \(53.1^\circ\).
Hence show that one solution of \(3\cos \theta + 4\sin \theta = 2\) is approximately \(120^\circ\).
State all the other solutions for \(0^\circ \leq \theta \leq 500^\circ.\)
Hence give the positive values of \(\theta\) less than \(500^\circ\) for which \(3\cos \theta + 4\sin \theta > 2\).