underground
mathematics
Discuss
Map
Search
Browse
User
More
Home
How-to guide
Underground hub
About and contact
Your mathematical classroom
Exit fullscreen mode
Chain Rule & Integration by Substitution
Review question
Can we carry out these three tricky integrals?
Add to your resource collection
Remove from your resource collection
Add notes to this resource
View your notes for this resource
Ref: R8778
Printable/supporting materials
Printable version
Fullscreen mode
Teacher notes
Question
Suggestion
Solution
Question
Find
\(\displaystyle \int x \sqrt{2x-1} \:dx\)
,
\(\displaystyle \int \frac{1}{\sqrt{2x - x^2}} \:dx\)
.
Evaluate
\(\displaystyle \int_0^{\pi/4} \sec^4 x \:dx\)
.
Previous
Next
Station
Chain Rule & Integration by Substitution
Lines
Functions
Calculus
Add to your collection
Add the current resource to your resource collection