Review question

# Can we carry out these three tricky integrals? Add to your resource collection Remove from your resource collection Add notes to this resource View your notes for this resource

Ref: R8778

## Suggestion

(a)(ii) Find $\displaystyle \int \frac{1}{\sqrt{2x - x^2}} \:dx$.

Could we try completing the square on the denominator?

1. Evaluate $\displaystyle \int_0^{\pi/4} \sec^4 x \:dx$.

What do we get if we differentiate $\tan x$?