Review question

# Can we find an approximation to $(1.0099)^6$? Add to your resource collection Remove from your resource collection Add notes to this resource View your notes for this resource

Ref: R7489

## Question

Obtain the first $4$ terms in the expansion of $(1 + p)^6$ in ascending powers of $p$.

By substituting $p = x - x^2$ obtain the expansion of $(1 + x - x^2)^6$ as far as the term in $x^2$.

Find a value for $x$ which would enable you to calculate $(1.0099)^6$.