Review question

# Can we find an approximation to $(1.0099)^6$? Add to your resource collection Remove from your resource collection Add notes to this resource View your notes for this resource

Ref: R7489

## Suggestion

By substituting $p = x - x^2$ obtain the expansion of $(1 + x - x^2)^6$ as far as the term in $x^2$.

How can we use our expansion from the first part of the question?

Find a value for $x$ which would enable you to calculate $(1.0099)^6$.

We want to use an expansion of $(1 + x - x^2)^6$ - can we find an equation that $x$ must satisfy?

Or can we see straight away what $x$ must be?