Review question

# How many roots are there to $x=8^{\log_2x} -9^{\log_3x}-4^{\log_2x}+\log_{0.5}{0.25}$? Add to your resource collection Remove from your resource collection Add notes to this resource View your notes for this resource

Ref: R5103

## Suggestion

The number of positive values $x$ which satisfy the equation $x=8^{\log_2x} -9^{\log_3x}-4^{\log_2x}+\log_{0.5}{0.25}$ is

1. 0;

2. 1;

3. 2;

4. 3.

Can we evaluate $\log_{0.5}{0.25}$ ?

We know that $8$ is a power of $2$ – could use this fact to rewrite $8^{\log_2x}$?