From the inequalities \[y-2x>0,\qquad x+y>3,\qquad 2y-x<5\] deduce that \[\frac{1}{3}< x < \frac{5}{3},\qquad 2< y <\frac{10}{3},\]
Where do the three lines
\[\begin{align*}
y-2x &= 0 \\
x+y &=3 \\
2y-x &=5
\end{align*}\]
lie in the plane?
On which side of each of these lines does the respective inequality hold?
… and hence that the given inequalities cannot be satisfied simultaneously by integral values of \(x\) and \(y\).
Which integer values of \(x\) and \(y\) do we need to consider?
