A line cuts the axes to make a triangle; can we find its area?

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Three points have coordinates \(A(-2, -1)\), \(B(6, 9)\) and \(C(2, -3)\). The line through the midpoint of \(AB\) parallel to \(AC\) meets the \(x\)-axis at \(X\) and the \(y\)-axis at \(Y\). Calculate the coordinates of \(X\) and \(Y\).

It is always helpful to draw a sketch of a geometric situation.

We are given coordinates of points; how can we use these to find the equation of the new line?