Show that the equation \(x^3 - 6x^2 + 12 = 0\) has two positive roots and one negative root. Show that the negative root lies between \(-1\) and \(-1.5\) and find it correct to one decimal place.
Polynomials & Rational Functions
Question
Show that the equation \(x^3 - 6x^2 + 12 = 0\) has two positive roots and one negative root. Show that the negative root lies between \(-1\) and \(-1.5\) and find it correct to one decimal place.