The equation \[(x^2+1)^{10} = 2x - x^2 - 2\]

  1. has \(x=2\) as a solution;

  2. has no real solutions;

  3. has an odd number of real solutions;

  4. has twenty real solutions.

We can complete the square on the right-hand side of the equation to give \[(x^2+1)^{10} = -1 - (x-1)^2.\]

Now for real \(x\), the left-hand side of this equation is always positive, but the right-hand side is always negative, so the equation has no real solutions.

Therefore the answer is (b).

The graphs of \(y=(x^2+1)^{10}\) and \(y= -1 - (x-1)^2\) help us to see what is going on.

graphs of the two curves given in the question