What fraction of the large square is each shaded square? Write the total shaded area as a sum of fractions.
The fractions of each shaded square form a geometric sequence.
If we make the assumption that this pattern will be infinite, then the sum of the fractions will be \[\dfrac{1}{4} + \dfrac{1}{16}+ \dfrac{1}{64}+ \dfrac{1}{256} + \dotsb \text{ or } \dfrac{1}{4} + \dfrac{1}{4^2}+ \dfrac{1}{4^3}+ \dfrac{1}{4^4} + \dotsb\]
Do we know anything about the value of this sum? What must it be bigger than? What must it be smaller than?
If the area of the large square is 1, what is the total sum of the shaded area?
There are many ways the total of this sum can be found, but what do we see in the image below?
There are different ways to think about this image, but one is:
We have the same sequence appearing three times, and covering the whole of the square so \[\dfrac{1}{4} + \dfrac{1}{4^2}+ \dfrac{1}{4^3}+ \dfrac{1}{4^4} + \dotsb = \dfrac{1}{3}.\]
What fraction of the large square is each shaded triangle? Write the total shaded area as a sum of fractions.
To start finding the fraction of each triangle we need to make some assumptions. We will assume that the diagonal lines that form the next square come from the midpoints of the larger square. There are many ways we could find the areas of triangles and the relationships between them, but we will think about similar triangles.
Why are the two triangles similar? What is the length scale factor from the smaller to the larger one? What about the area scale factor?
The larger triangle has sides that are double the length of the smaller triangle, and since they are similar, the area is four times as big.
The two triangles together give \(\dfrac{1}{4}\) of the square. Since the bigger triangle is \(\dfrac{4}{5}\) of \(\dfrac{1}{4}\), it’s \(\dfrac{1}{5}\) of the whole square.
What is the area of the smaller square?
If the area of the large square is 1, what is the total sum of the shaded area in each case?
Each square is \(\dfrac{1}{5}\) of the area of the previous square, so each triangle is \(\dfrac{1}{5}\) of the area of the previous triangle. If the area of the large square is \(1\), the total shaded area is therefore \[\dfrac{1}{5} + \dfrac{1}{5^2} + \dfrac{1}{5^3} + \dfrac{1}{5^4}+ \dotsb \text{ or } \dfrac{1}{5} + \dfrac{1}{25} + \dfrac{1}{125} + \dfrac{1}{625}+ \dotsb.\]
If we think about the image from the warm-up then we see that this sum is equal to \(\dfrac{1}{4}\).
Can other sums of fractions be thought about in a similar way? Is it possible to draw a diagram that represents the following sums?
\[\dfrac{1}{2} + \dfrac{1}{4} + \dfrac{1}{8}+ \dfrac{1}{16}+ \dotsb\] \[\dfrac{1}{3} + \dfrac{1}{9} + \dfrac{1}{27} + \dfrac{1}{81} + \dotsb\]
Here are suggestions for each sum.
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What is the total of each sum?
Using the diagrams we can see the total of the sums. \[\dfrac{1}{2} + \dfrac{1}{4} + \dfrac{1}{8}+ \dfrac{1}{16}+ \dotsb = 1\] \[\dfrac{1}{3} + \dfrac{1}{9} + \dfrac{1}{27} + \dfrac{1}{81} + \dotsb = \dfrac{1}{2}\]
From above we have: \[\dfrac{1}{4} + \dfrac{1}{16}+ \dfrac{1}{64}+ \dfrac{1}{256} + \dotsb = \dfrac{1}{3}\] \[\dfrac{1}{5} + \dfrac{1}{25} + \dfrac{1}{125} + \dfrac{1}{625}+ \dotsb = \dfrac{1}{4}\]
Can you use these infinite sums to find the total of others? For example, can you find the total sum of \(\dfrac{1}{2} + \dfrac{1}{10} + \dfrac{1}{50} + \dfrac{1}{250} + \dotsb\)?
Is it possible that other sums of fractions will sum to the same totals? For example, can you find another infinite sum that equals \(\dfrac{1}{4}\)?
