What is this multiple of $13$'s final digit?

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The four digit number \(2652\) is such that any two consecutive digits from it make a multiple of \(13\). Another number \(N\) has this same property, is \(100\) digits long and begins in a \(9\). What is the last digit of \(N\)?

1. 2

2. 3

3. 6

4. 9

What are the two digit multiples of \(13\)?