In the range \(0 \le x < 2\pi\) the equation \[\cos(\sin x) = \frac{1}{2}\] has
no solutions;
one solution;
two solutions;
three solutions.
First consider \[\cos y = \frac{1}{2};\] what are the solutions of this equation?
From this, can you find the values of \(\sin x\) that satisfy \[\cos(\sin x) = \frac{1}{2}?\]
Do all or any of these values of \(\sin x\) give a solution for \(x\)?