In the range \(0 \le x < 2\pi\) the equation \[\cos(\sin x) = \frac{1}{2}\] has

no solutions;

one solution;

two solutions;

three solutions.

First consider \[\cos y = \frac{1}{2};\] what are the solutions of this equation?

From this, can you find the values of \(\sin x\) that satisfy \[\cos(\sin x) = \frac{1}{2}?\]

Do all or any of these values of \(\sin x\) give a solution for \(x\)?