Prove that the equation of the normal to the ellipse \(x^2/a^2 + y^2/b^2=1\) at the point \(P\,(a\cos\theta,b\sin\theta)\) is \[\frac{ax}{\cos \theta} - \frac{by}{\sin \theta} = a^2-b^2.\]
If there is a value of \(\theta\) between \(0\) and \(\pi/2\) such that the normal at \(P\) passes through one end of the minor axis, show that the eccentricity of the ellipse must be greater than \(1/\sqrt{2}\).
