Suggestion

We now know that given three distinct points in the plane, there is (usually) a unique circle passing through them.

So if we are given three points, we would like to find the equation of the circle that passes through them. How many ways can you find to do this?

An algebraic approach

Might the general equation of a circle be of use here?

We want to find an equation of the form \((x-a)^2 + (y-b)^2 = r^2\), where \((a,b)\) is the (unknown) centre of the circle and \(r\) is the (unknown) radius. We have \(3\) points that lie on the circle, so we can use these to get some simultaneous equations…

A slightly more geometric way to think about this approach is that we know that the centre, say \((a,b)\), is at an equal distance from all points. So we could write down the distances from \((a,b)\) to our known points, and then equate those…

A geometric approach

If we have two (distinct) points, then there are many circles that pass through both points. Can you say anything about the centres of these circles? Might that help us when we know a third point on the circle?

This GeoGebra applet might be helpful to explore this. The two points \(A\) and \(B\) (in red) are fixed, while the third point \(C\) (in blue) can be moved. The centre of the circle through these three points, labelled \(O\), can be seen, and leaves a trace as you move \(C\).

Can you explain the behaviour you have observed? And how can this help us to find the equation of the circle when we know a third point on the circumference?

Let’s call the three given points \(A\), \(B\) and \(C\).

The centre of the circle must be the same distance from \(A\), \(B\) and \(C\). Those points which are the same distance from \(A\) and \(B\) lie on the …

What about those points which are the same distance from \(A\) and \(C\)?

Is that enough to find the centre?