Given that \[5x^2 + 2y^2 − 6xy + 4x − 4y \equiv a (x − y + 2)^2 + b (cx + y)^2 + d,\] find the values of the constants \(a\), \(b\), \(c\) and \(d\).
Solve the simultaneous equations \[\begin{align*} 5x^2 + 2y^2 − 6xy + 4x − 4y &= 9 , \\ 6x^2 + 3y^2 − 8xy + 8x − 8y &= 14 . \end{align*}\]Quadratics
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