The inequalities \(x^2 + 3x + 2 > 0\) and \(x^2 + x < 2\) are met by all \(x\) in the region:
\(x < -2\);
\(-1 < x < 1\);
\(x > -1\);
\(x > -2\).
Quadratics
Question
The inequalities \(x^2 + 3x + 2 > 0\) and \(x^2 + x < 2\) are met by all \(x\) in the region:
\(x < -2\);
\(-1 < x < 1\);
\(x > -1\);
\(x > -2\).