Review question

# When does $3x^4 - 16x^3 +18x^2 + k = 0$ have four real solutions? Add to your resource collection Remove from your resource collection Add notes to this resource View your notes for this resource

Ref: R8959

## Question

The equation in $x$, $3x^4 - 16x^3 +18x^2 + k = 0$ has four real solutions

1. when $-27 < k < 5$;

2. when $5< k <27$;

3. when $-27< k <-5$;

4. when $-5 < k <0$.