Exit fullscreen mode

Calculus meets Functions

Review question

When does $3x^4 - 16x^3 +18x^2 + k = 0$ have four real solutions?
Add to your resource collection Remove from your resource collection Add notes to this resource View your notes for this resource

Ref: R8959

Printable/supporting materials Printable version Fullscreen mode Teacher notes

Question

The equation in \(x\), \[3x^4 - 16x^3 +18x^2 + k = 0\] has four real solutions

when \(-27 < k < 5\);
when \(5< k <27\);
when \(-27< k <-5\);
when \(-5 < k <0\).