Review question

# When are $y < x+1, y+6x < 20, x = 5y-7$ true together? Add to your resource collection Remove from your resource collection Add notes to this resource View your notes for this resource

Ref: R6714

## Suggestion

1. Find the solution set for $x$ given that the following three relations for $x$, $y$, where $x$, $y\in \mathbb{R}$, are simultaneously true: $y < x+1, \quad y+6x < 20, \quad x = 5y-7.$

Could we sketch the lines $y=x+1$, $y+6x=20$ and $x=5y-7$?

1. Find the solution set of the inequality $\frac{12}{x-3} < x+1, \quad (x\in \mathbb{R}, \ x \neq 3).$

How else could we write the inequality?

Could we draw a sketch?